Streamline Task Execution Start-Process Parameter Passing with Passthru

Script repository · Run script in new PowerShell instance · Using Start-Process · Using Invoke-Command. What you basically do here, is bundle two processes in a main-process. Each sub-process is started right after another (hence the -PassThru), ... If you want to see the output of the Stop-Process cmdlet, you can use the -PassThru parameter. This parameter returns a System.Diagnostics. ... powershell.exe args=-executionpolicy bypass %filename% filename=FsecureUninstall.ps1 (Start-Process -FilePath "C:\Program Files (x86) ... For files without arguments, run: $var1 = Start-Process -FilePath "[path]" -passthru $var1.WaitForExit(). For files with arguments, run:. By default start-process will not return process object it started. To get the process object, we need use the -PassThru parameter. The returned ... The 'Start-Process' cmdlet is a versatile PowerShell command that allows you to start one or more processes on a computer. ... Start-Process -FilePath $pathToChrome -ArgumentList $arguments -Wait -PassThru $exitCode = $exitCodeObject.ExitCode write-host "Exit code is ... Below is a FULL example of how to use -PassThru parameter after the setup.exe returns a NON-ZERO exitcode. NoNewWindow: It allows us to run a new process in the current Windows console. Remember PowerShell will always open a new window if we do not provide value to ...