Unlock the Power of PowerShell Passing Parameters to Processes

For files without arguments, run: $var1 = Start-Process -FilePath "[path]" -passthru $var1.WaitForExit(). For files with arguments, run:. For example, there are many Windows PowerShell cmdelts that simply work, and they do not return any data. An example is the Start-Process cmdlet ... Resulta que el problema era que faltaba el parámetro "-PassThru", ya que, por defecto, el cmdlet Start-Process no genera ninguna salida, por ... Use the same argument list variable Start-Process Test.exe -ArgumentList $arguments -Wait . ... PassThru -Wait -RedirectStandardError ... Unfortunately, Start-Process cmdlet in Powershell will not return the PID of the process after starting it. So we need to depend on [Diagnostics ... Start-Process is used to run a command line executable or script the output will show in a separate console window. ... PassThru. This command ... 1 and PS7+ show the outputs of dotnet.exe as long as I have "-NoNewWindow" enabled on Start-Process (which I do). " $process = Start-Process -FilePath msiexec.exe -ArgumentList $arguments -Wait -PassThru if ($process.ExitCode -eq 0){ Write-Verbose "$msiFile has been ... With the Passthru parameter, PowerShell returns the output in the console. For example, below notepad.exe process with ID 12344 will be stopped. ... PassThru'" as PowerShell error, then likely the PowerShell version is too old to support -PassThru, which likely means you have are running ...