Unlock the Secrets of PowerShell Passthru Parameters and Start-Process Demystified

By default start-process will not return process object it started. To get the process object, we need use the -PassThru parameter. The returned ... Open the PowerShell environment ... 1. In order to open a PowerShell window, type powershell into the Start menu search field and click on Run as ... Script repository · Run script in new PowerShell instance · Using Start-Process · Using Invoke-Command. Use the same argument list variable Start-Process Test.exe -ArgumentList $arguments -Wait . ... PassThru -Wait -RedirectStandardError ... For example, there are many Windows PowerShell cmdelts that simply work, and they do not return any data. An example is the Start-Process cmdlet ... The Start-Process cmdlet starts one or more processes on the local computer. By default, Start-Process creates a new process that inherits all ... If you want to see the output of the Stop-Process cmdlet, you can use the -PassThru parameter. This parameter returns a System.Diagnostics. " $process = Start-Process -FilePath msiexec.exe -ArgumentList $arguments -Wait -PassThru if ($process.ExitCode -eq 0){ Write-Verbose "$msiFile has been ... 2. $p = Start-Process -FilePath cmd -ArgumentList "/c exit 123" -PassThru. $p .ExitCode ; $p .get_ExitCode() ; 2. 3. 4. 5. Exception calling " ... What you basically do here, is bundle two processes in a main-process. Each sub-process is started right after another (hence the -PassThru), ...