Empower Your Automation Start Powershell Processes with Passthru

" $process = Start-Process -FilePath msiexec.exe -ArgumentList $arguments -Wait -PassThru if ($process.ExitCode -eq 0){ Write-Verbose "$msiFile has been ... batch 파일처럼 exit code를 가져오면 되는가 싶었더니 옵션이 따로 있었다. Start-Process -PassThru Pamameter. 프로세스 개체를 반환하는 파라미터 - ... -wait を使うと、 Start-Process を同期で行う。 -PassThru を使うとプロセスIDを取得できる． 実行したアプリを消すとき等に利用できる． $Process = Start-Process -FilePath $ClientExecutablePath -ArgumentList $Parameters -PassThru if($WaitForExit){ Write-Verbose -Message “Waiting for the ... This method has gained a bit more legitimacy in some use cases though, and in PowerShell v2, is now accessible using the Start-Process cmdlet. The Start-Process cmdlet starts one or more processes on the local computer. By default, Start-Process creates a new process that inherits all the environment ... Start cmd.exe from powershell and note the PID. PS > $x = Start-Process cmd.exe -PassThru PS > $x.id 23652. From the command ... To run an executable using PowerShell, use the Start-Process cmdlet. For example, Start-Process -FilePath "C:\Path\To\YourExecutable.exe" . ... Start-Process -FilePath "\\hestia\TA\Genesis Provider Desktop v19 ... Passthru -Wait I have tried using the Ivanti Management console ... 7.4.0 Start-Process with -PassThru & -RedirectStandardOutput does not return the process object completely ( properties like Exitcode ) #20716.