Supercharge Your Workflow Start Processes with PowerShell and PassThru

7.4.0 Start-Process with -PassThru & -RedirectStandardOutput does not return the process object completely ( properties like Exitcode ) #20716. NAME Start-Process SYNOPSIS Starts one or more processes on the local computer. SYNTAX Start-Process [-FilePath] [[-ArgumentList] ] ... Advanced PowerShell Functions: Begin to Process to End · Create a ... The PassThru Parameter: Gimme Output · Update-OneGet: Install OneGet ... No problems. You could improve your script by assigning a variable to "Start-Process" and then check it's exitcode to determine whetever it was ... ... Start-Process -FilePath $pathToChrome -ArgumentList $arguments -Wait -PassThru $exitCode = $exitCodeObject.ExitCode write-host "Exit code is ... By default start-process will not return process object it started. To get the process object, we need use the -PassThru parameter. The returned ... This method has gained a bit more legitimacy in some use cases though, and in PowerShell v2, is now accessible using the Start-Process cmdlet. ... PassThru $process.HasExited $process.ExitCode $process = Start-Process ... PowerShell: How to get exit code of a process. Depending on the exit code you ... If you specify a non-executable file, Start-Process starts the program that is associated with the file, similar to the Invoke-Item cmdlet. You can use the ... For example: Start-Process Powershell -Verb RunAs -WorkingDirectory . creates a new shell in the current directory with elevated permissions.